From: Suraya Zulkepli (kinrara_16$##$yahoo.com)
Date: Thu Sep 04 2008 - 18:03:05 EDT
Hello everyone,
can
anyone show me the mechanism of iodolactonization by using
methyl-hex-5-enoate..(methyl ester unsaturated acid) and use the
condition I2 and CH3CN..?Do you think the methyl group adjacent to the
oxygen can cleave the bond easily to form 6-membered ring lactone
without hydrolysis process?
Plz help me..
Thank you
Suraya
_______________________________________________
ORGLIST - Organic Chemistry Mailing List
Website / Archive / FAQ: http://www.orglist.net
To post a message (TO EVERYBODY) send to everybody$##$orglist.net
To unsubscribe, send to everybody-request$##$orglist.net the message: unsubscribe your_orglist_password your_address
This archive was generated by hypermail 2.1.4 : Wed Feb 11 2009 - 12:37:18 EST