RE: ORGLIST: epoxidation help

Date view Thread view Subject view Author view Attachment view

From: will jones (willjones46$##$hotmail.com)
Date: Mon Oct 24 2005 - 17:06:47 EDT


So if your H2O2 is 9.8M, then in 1L of it, you have 9.8mol of H2O2.
In 100mL you therefore have 0.98mol and if you want to know how much is in
115mL, then..
0.98x1.15=1.127mol. That's how they got it.

Will


>From: Sunil Silvary <sunil.silvary$##$gmail.com>
>To: everybody$##$orglist.net
>Subject: ORGLIST: epoxidation help
>Date: Sun, 23 Oct 2005 21:34:35 -0400
>
>Hi,
>I am doing an epoxidation reaction and following the procedure given in
>org.syn vol IV in the procedure it is given that 1.2 moles of H2O2 is
>115ml.
>I do not understand how they got that value. The H202 that I bought from
>aldrich has a density of 1.11 gm/ml and molarity of 9.8M. I tried
>calculating as usual by using and molarity=moles/litre and d=m/v
>relationship but i am not getting that value.
> Is there is special way for converting moles to volume for H2O2 ? Please
>help if you know the method, if possible in detail.
> thanking you,
>sunil


>_______________________________________________
>ORGLIST - Organic Chemistry Mailing List
>Website / Archive / FAQ: http://www.orglist.net
>To post a message (TO EVERYBODY) send to everybody$##$orglist.net
>To unsubscribe, send to everybody-request$##$orglist.net the message:
>unsubscribe your_orglist_password your_address


_______________________________________________
ORGLIST - Organic Chemistry Mailing List
Website / Archive / FAQ: http://www.orglist.net
To post a message (TO EVERYBODY) send to everybody$##$orglist.net
To unsubscribe, send to everybody-request$##$orglist.net the message: unsubscribe your_orglist_password your_address



Date view Thread view Subject view Author view Attachment view

This archive was generated by hypermail 2.1.4 : Thu Feb 18 2010 - 16:58:10 EST