RE: ORGLIST:doubt

From: Yuehui Zhou (yuehuizhou$##$hotmail.com)
Date: Thu Sep 12 2002 - 01:19:29 EDT

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O=P(CH3)2 is a wrong writing, either you have O=P(CH3)3, trimethylphosphine
oxide, or you have O=PH(CH3)2, dimethylphosphine oxide. Phosphonic acid
should be penta-valent too. SO it should be O=P(CH3)2(OH). Phosphonium
attaches 4 radicals, but it's a cation.

Y. Zhou,

Phosphine Technology,
Cytec Canada

>From: Jim Mitchell <j_mitchell$##$cerilliant.com>
>To: "'sweta nigam'" <sweta_n$##$atc.tcs.co.in>,"everybody$##$orglist.net"
><everybody$##$orglist.net>
>Subject: RE: ORGLIST:doubt
>Date: Wed, 11 Sep 2002 08:37:02 -0500
>
>This probably is a phosphonic acid: O=P(CH2)OH, but yes, you are correct,
>Phosphorous is typically pentavalent.
>
>Jim Mitchell
>Cerilliant Corporation
>
>-----Original Message-----
>From: sweta nigam [SMTP:sweta_n$##$atc.tcs.co.in]
>Sent: Wednesday, September 11, 2002 7:21 AM
>To: everybody$##$orglist.net
>Subject: ORGLIST:doubt
>
> << File: ATT00003.html >> hello sir
> i am sweta employee in tata consultancy services hyderabad(india)
>i have a doubt regarding the compound of phosphorus :do 0=P(CH3)2 exists as
>i think phosphorus should have been attached to either 3 or 5 and here we
>have 4 bonds?
>if possible do help me ..
>thanka & regards
>sweta
>
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