From: J.N.Iley$##$open.ac.uk
Date: Tue Aug 06 2002 - 10:33:31 EDT
Jacob
It means enantiomeric excess.....a 98%ee equates to 99% of one enantiomer
and 1% of the other
Jim
> -----Original Message-----
> From: zabicky$##$bgumail.bgu.ac.il [SMTP:zabicky$##$bgumail.bgu.ac.il]
> Sent: 06 August 2002 13:45
> To: everybody$##$orglist.net
> Subject: ORGLIST:On optical purity
>
> Dear Friends,
>
> I've seen recently a phase like "the (-)-xxx isomer (98%ee)".
>
> What does "ee" after the percent symbol mean?
>
> All the best,
>
> Jacob
>
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> Prof. Jacob Zabicky
> Institutes for Applied Research
> Ben-Gurion University of the Negev Private: POB 12366, Beer-Sheva
> 84863
> POB 653, Beer-Sheva 84105, ISRAEL Tel. +972-8-6496792
> http://profiler.bgu.ac.il/site/main.cfm
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