From: Javier Cuesta-Perez (javier$##$icr.ac.uk)
Date: Mon Jul 23 2001 - 06:44:26 EDT
So far I have received these answers:
personally, i believe that the HDO cube would sink, as it
is heavier than the H2O cube, but the HDO wouldn't sink as
far as the D2O.
paul
- Yo creo que debe de flotar,
Pues si lo que hace flotar al hielo normal es que el
arreglo de puente de H en forma de una estructura hexagonal
con huecos, se debe de formar un puente en el HDO.
Felipe Correa.
I would say that it should sink, being that Deuterium is
present.
Jumping off my soapbox......weee!
Cheers!
--
George D. 'Merlin' McCallion, Chemist
Sanofi-Synthelabo
25 Great Valley Parkway
Malvern, PA 19355
United States
Office: 610.889.6294
Fax: 610.889.6367
E: George.McCallion$##$sanofi-synthelabo.com
Hello Javier,
>>From the data you gave, IMHO there is no way of telling.
The density of ice and water is strongly influenced by
hydrogen bonding. Deuterium bonding is weaker, but I do not
know to what extent does that affect the
crystalline parameters at a given temperature. For example,
a weaker H-bonding may mean a mere 2% increase of the
average O-O nearest neighbor distances. The
lower theoretical (crystalline) density thus obtained will
compensate for nearly 5.6% increase in molecular mass and
make the half-deuterated ice float.
All the best,
Jacob
_______________________________________
Dr Javier Cuesta-Perez
javier$##$icr.ac.uk
Biomolecular Structure Unit
The Institute of Cancer Research
15 Cotswold Rd
Sutton, Surrey
SM2 5NG, UK
Phone:(+44) (0)20 8643 8901 (ext. 4568)
Fax: (+44) (0)20 8643 1675
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