From: Dr. D.Basavaiah-(RS) (dbscrs$##$uohyd.ernet.in)
Date: Fri Sep 29 2000 - 14:35:12 EDT
Dear Mr. Swamy:
You should understand, that formation of acryloyl chloride takes some
induction time and temperature.
You do this way:
Mix your acrylic acid and benzoylchloride in the usual proportions in a
1Lrbflask. set up a double surfaced condensor/receiver etc. add a pinch of
hydroquinone in the receiving flask. Heat the rb using a mantle HCl gas is
released abundantly, and you can notice fumes at the guarde neck of
receiving flask (perhaps, color change of your blue" silicagel to 'green")
Nothing comes out. Heat the rb almost to boiling. (This is at least four
folds to that of the b.p. of acryloyl chloride (it is around 75C) Then you
can observe your compound getting distilled out. But how do you know, that
it is acryloylchloride and not acrylic acid or benzoyl chloride?
Use a thermometer on the top of still head. Temperature will not shoot oup
beyond 100 deg. C. Continue distillation, till all acryloyl chloride
distills out. The yield is Quantitative!
You cant miss this. Remember to havave patience!
Good luck
Krishnamacharyulu
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Research Scholar
School of chemistry Telephone: 3010500 extn:4807
University Of Hyderabad
Hyderabad- 500 046
India
e-mail: dbscrs$##$uohyd.ernet.in
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