Re: ORGLIST: Oxidation States of Carbon

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From: Manuel Toennis (mt$##$linda.org.chemie.tu-muenchen.de)
Date: Wed Aug 05 1998 - 03:24:09 EDT


Dear Jeff,

look at the occuring elements and their electronegativity values.
Oxygen has the highest one, thereforeit will always be in an oxidation
state of -2, while each of ir's partners will gain a positive 'charge'.
Hydrogen is most elecropositve element here, ist has always +1, giving
his partner a negative 'charge'. Now look at the carbon atoms. There are
tree diffent kinds. An aldehyde, HRC=O, four secondary Alkohols RR'HC-OH
and one primary alcohol, H2RC-OH. For the aldehyde the calculation is
like this: a double bound oxygen gives the carbon a +2 formal charge, the
hydrogen adds -1 and the bond to the next carban 0 (both atoms are
equal), so the result ist +1. the secondary alcohl carbons are at 0
(+1 -1 + 2*0), the primary at -1.

Bye, Manuel Tvnnis




> > A colleague of mine has an interest in the average oxidation state of
> > carbon in cellulose. Does anyone have any ideas about how to calculate
> > this value or where one might find such information.
> >
> > ********************************************************************************
> > Jeff Frick Phone: 309-556-3159
> > Department of Chemistry Fax: 309-556-3864
> > Illinois Wesleyan University email: jfrick$##$titan.iwu.edu
> > Bloomington, IL 61701
> > ********************************************************************************
> >
> >
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